Aldehydes, Ketones and Carboxylic Acids Class 12 PDF

The aldehydes, ketones and carboxylic acids class 12 chapter is Chapter 3 of NCERT’s Class 12 Chemistry Part II textbook — 32 printed pages in the current 2026-27 reprint — and the official PDF is right below, followed by a section-by-section guide to everything the book contains.

Use this page two ways: grab the chapter file first so you can read it yourself, then return here for the mechanisms, naming rules, acidity logic and exam-style practice that the chapter assumes you already know.

Download the NCERT Class 12 Chemistry Chapter 3 Aldehydes, Ketones and Carboxylic Acids PDF — the official chapter file straight from ncert.nic.in, so you can work through the figures and the twenty closing exercises on paper or on your phone.

If you want to confirm the current edition or download the whole book instead, the official NCERT textbook portal lists every title.

Reference: NCERT Class 12 Chemistry Part II textbook, chapter 3, official edition on ncert.nic.in.


What the chapter holds Count Where it is used
Printed pages 32
Sections in the chapter 17
Figures with NCERT captions 32
Tables 6
Worked examples 3 solved step by step in our NCERT Solutions
Exercise questions 20 answered in our NCERT Solutions
Official NCERT PDF Download the chapter PDF the chapter exactly as NCERT publishes it


Aldehydes, ketones and carboxylic acids are widespread in plants and animal kingdom.
Aldehydes, ketones and carboxylic acids are widespread in plants and animal kingdom. Source: NCERT
The common names of ketones are derived by naming two alkyl or aryl groups bonded to the carbonyl group.
The common names of ketones are derived by naming two alkyl or aryl groups bonded to the carbonyl group. Source: NCERT
The IUPAC names of open chain aliphatic aldehydes and ketones are derived from the names of the corresponding alkanes by replacing the ending $-e$ with $-al$ and $-one$ respectively.
The IUPAC names of open chain aliphatic aldehydes and ketones are derived from the names of the corresponding alkanes by replacing the ending $-e$ with $-al$ and $-one$ respectively. Source: NCERT
Side chain chlorination of toluene gives benzal chloride, which on hydrolysis gives benzaldehyde.
Side chain chlorination of toluene gives benzal chloride, which on hydrolysis gives benzaldehyde. Source: NCERT
When benzene or its derivative is treated with carbon monoxide and hydrogen chloride in the presence of anhydrous aluminium chloride or cuprous chloride, it gives benzaldehyde or substituted…
When benzene or its derivative is treated with carbon monoxide and hydrogen chloride in the presence of anhydrous aluminium chloride or cuprous chloride, it gives benzaldehyde or substituted… Source: NCERT
8.2 Write the structures of products of the following reactions:
8.2 Write the structures of products of the following reactions: Source: NCERT
The lower members of aldehydes and ketones such as methanal, ethanal and propanone are miscible with water in all proportions, because they form hydrogen bond with water.
The lower members of aldehydes and ketones such as methanal, ethanal and propanone are miscible with water in all proportions, because they form hydrogen bond with water. Source: NCERT
Compound (B), being an oxidation product of a ketone should be a carboxylic acid.
Compound (B), being an oxidation product of a ketone should be a carboxylic acid. Source: NCERT

Aldehydes, Ketones and Carboxylic Acids Class 12: Chapter 3 at a Glance

The table below lists what the chapter holds — its sections, figures, worked examples and exercise questions — so you know the chapter’s size before you start reading.

How the Chapter Is Organised: Three Families, One Functional Group

This chapter studies three families that share one functional group — the carbonyl group, \( \textgreater\text{C=O} \) — and it treats each family in the same order: nomenclature, structure, preparation, physical properties, reactions, then uses.

General formula of aldehydes, ketones and carboxylic acids class 12: the carbonyl group bonded to a carbon and hydrogen in an aldehyde, to two carbons in a ketone, and to a hydroxyl in a carboxylic acid
In aldehydes, the carbonyl group is bonded to a carbon and hydrogen while in the ketones, it is bonded to two carbon atoms. Source: NCERT

Read the figure above as the chapter’s opening frame. In an aldehyde (R–CHO) the carbonyl carbon carries one carbon and one hydrogen; in a ketone (R–CO–R) it carries two carbon atoms; in a carboxylic acid (R–COOH) the carbonyl is attached to a hydroxyl group, and that combined –COOH unit is called the carboxyl group.

The chapter has two halves. Aldehydes and ketones come first, then carboxylic acids in the same order. It closes with its own Summary and a twenty-question exercise set, and it assumes you have already met alcohol oxidation and Grignard reagents in the previous chapter — both return here constantly.

The Carbonyl Group: Why Aldehydes and Ketones React This Way

Everything in this chapter depends on the structure of one functional group, so the book establishes that structure before any reaction. Understand the carbonyl group and every mechanism that follows becomes the same story.

  • The carbonyl carbon is sp² hybridised and forms three sigma bonds. Its fourth valence electron sits in a p-orbital and forms a pi bond with oxygen.
  • The carbon, the oxygen and the two attached atoms lie in one plane, with bond angles near 120°, and the pi electron cloud lies above and below that plane.
  • Oxygen is more electronegative than carbon, so the group is polar: the carbon is the electrophilic (Lewis acid) centre and the oxygen is the nucleophilic (Lewis base) centre. Carbonyl compounds have substantial dipole moments — larger than ethers’ — explained by resonance between a neutral and a dipolar structure.

The consequence drives the whole chapter: nucleophiles attack the carbon of a carbonyl — the opposite of alkene chemistry, where electrophiles attack. That is why the next sections are all nucleophilic additions.

Naming Carbonyl Compounds: Common and IUPAC Rules

Every exercise in this chapter assumes you can name the compound first. Learn the pattern once, and the IUPAC names stop being a memory load.

  • Aldehydes: replace the alkane ending –e with –al. The chain is numbered from the carbonyl carbon.
  • Ketones: replace –e with –one. Number the chain from the end nearer the carbonyl group.
  • Carboxylic acids: replace –e with –oic acid. The carboxyl carbon is numbered 1.
  • Ring aldehydes: add the suffix carbaldehyde after the cycloalkane name; benzenecarbaldehyde is normally just called benzaldehyde.

Common names use Greek letters: the α-carbon is the one directly bonded to the carbonyl, then β, γ, δ and so on. The common names themselves come from Latin or Greek sources — formic acid from ants (formica), acetic acid from vinegar (acetum).

Work three of your own: 2-methylpropanal (an aldehyde with a methyl branch on carbon 2), pentan-2-one (a five-carbon ketone with the carbonyl on carbon 2), and benzene-1,2-dicarbaldehyde (two aldehyde groups on neighbouring ring carbons). The book’s Table 8.1 (aldehydes and ketones) and Table 8.3 (carboxylic acids) hold the full lists of common and IUPAC names.

Reading NCERT’s Key Diagrams: Carbonyl and Carboxyl Structures

These structural diagrams appear throughout the chapter, and the mechanisms are far easier once you can read them. Each one carries a piece of the same story: where the electrons sit and where they move.

Orbital diagram showing the planar trigonal sigma framework of the carbonyl carbon with the pi electron cloud above and below the plane
Orbital diagram for the formation of carbonyl group (Fig. 8.1). Source: NCERT
Neutral and dipolar resonance forms of the carbonyl group, showing how the group becomes polarised
Orbital diagram for the formation of carbonyl group — the neutral and dipolar resonance forms (Fig. 8.1). Source: NCERT

Fig. 8.1 comes in two parts. The first shows the sigma framework — flat, trigonal, with the pi cloud above and below the plane. The second shows the neutral (A) and dipolar (B) resonance structures; the dipolar form is what gives the carbon its electrophilic character.

Nucleophile attacking the carbonyl carbon from above the plane, forming a tetrahedral alkoxide intermediate that captures a proton
Nucleophilic attack on carbonyl carbon (Fig. 8.2). Source: NCERT

Fig. 8.2 is the chapter’s central mechanism. The nucleophile approaches roughly perpendicular to the plane, the carbon rehybridises from sp² to sp³, a tetrahedral alkoxide intermediate forms, and that intermediate captures a proton from the medium to give the neutral addition product. Net result: Nu⁻ and H⁺ added across the C=O.

Carboxyl group with its three bonds to the carboxyl carbon lying in one plane at about 120 degrees and resonance delocalising charge onto the second oxygen
In carboxylic acids, the bonds to the carboxyl carbon lie in one plane and are separated by about 120°. Source: NCERT

The carboxyl diagram shows why acids behave differently from aldehydes: the three bonds lie in one plane at about 120°, and resonance delocalises charge onto the second oxygen. That extra stabilisation makes the carboxyl carbon less electrophilic than an aldehyde’s carbonyl carbon — so acids do not undergo nucleophilic addition the way aldehydes do.

Key Terms You Must Be Able to Define

Exercise 8.1 of this chapter asks for ten definitions, and every one comes from a nucleophilic addition reaction. Learn the term with the reaction that produces it and you will not confuse them.

Term Plain definition Reaction that produces it
Cyanohydrin Carbonyl compound with –OH and –CN on the same carbon Carbonyl + HCN (base-catalysed; CN⁻ adds first)
Hemiacetal Product of adding one alcohol molecule across the C=O Carbonyl + 1 mol alcohol in dry HCl
Acetal Gem-dialkoxy compound from two alcohol molecules Carbonyl + 2 mol alcohol in dry HCl
Ketal Cyclic acetal from a ketone and a diol Ketone + ethylene glycol
Imine \(\textgreater\text{C=NH}\) derivative Carbonyl + ammonia
Schiff’s base Substituted imine, \(\textgreater\text{C=NR}\) Carbonyl + amine
Oxime \(\textgreater\text{C=N–OH}\) derivative Carbonyl + hydroxylamine
Hydrazone \(\textgreater\text{C=N–NH}_2\) derivative Carbonyl + hydrazine
Phenylhydrazone / 2,4-DNP derivative \(\textgreater\text{C=N–NH–C}_6\text{H}_5\) (phenyl) or with NO₂ groups (2,4-DNP); these give yellow, orange or red solids Carbonyl + phenylhydrazine / 2,4-dinitrophenylhydrazine — used to characterise aldehydes and ketones
Semicarbazone \(\textgreater\text{C=N–NH–C(=O)–NH}_2\) Carbonyl + semicarbazide; only the NH₂ attached to the C=O reacts
Aldol A β-hydroxy aldehyde Carbonyl compound with an α-hydrogen + dilute alkali

Two family definitions close the list. A carboxylic acid is a carbonyl group attached to a hydroxyl group — the carboxyl group. Fatty acids are the higher C₁₂–C₁₈ aliphatic acids found in natural fats as esters of glycerol.

Preparing Aldehydes and Ketones: The Routes You Must Know

A small set of routes makes aldehydes and ketones, and most are shared between the two families. The skill is knowing which reagent gives which product.

Method Starting material Reagent / condition Product or named reaction
Oxidation of alcohols Primary alcohol PCC Aldehyde
Hydrogenation of acyl chloride Acyl chloride H₂ over Pd/BaSO₄ Aldehyde — Rosenmund reduction
Reduction of nitriles Nitrile (RCN) SnCl₂ + HCl, then hydrolysis Aldehyde — Stephen reaction
Selective reduction Nitrile or ester DIBAL-H, then hydrolysis Aldehyde
From toluene Methylbenzene CrO₂Cl₂ (hydrolysis) Benzaldehyde — Etard reaction
From toluene Methylbenzene CrO₃ in acetic anhydride, then hydrolysis Benzaldehyde
Side-chain chlorination Toluene Cl₂, then hydrolysis of benzal chloride Benzaldehyde (commercial method)
Formylation of arenes Benzene CO + HCl, anhydrous AlCl₃ or CuCl Benzaldehyde — Gatterman–Koch reaction
Oxidation of alcohols Secondary alcohol CrO₃ or similar Ketone
Ozonolysis Alkenes O₃, then Zn dust / water Aldehydes, ketones, or both
Hydration of alkynes Alkynes H₂SO₄ + HgSO₄ All alkynes except ethyne give ketones
Acyl chloride + organocadmium Acyl chloride R₂Cd Ketone
Nitrile + Grignard Nitrile RMgX, then hydrolysis Ketone
Friedel–Crafts acylation Benzene Acyl chloride + anhydrous AlCl₃ Aryl ketone
Rosenmund reduction: an acyl chloride hydrogenated over palladium on barium sulphate to give an aldehyde
Acyl chloride (acid chloride) is hydrogenated over catalyst, palladium on barium sulphate. Source: NCERT

The first figure shows the Rosenmund reduction in action: the acyl chloride is hydrogenated, but the barium sulphate “poisons” the palladium catalyst so the reaction stops cleanly at the aldehyde instead of going further to the alcohol.

Friedel-Crafts acylation: benzene treated with an acid chloride in the presence of anhydrous aluminium chloride to give an aryl ketone
When benzene or substituted benzene is treated with acid chloride in the presence of anhydrous aluminium chloride, it affords the corresponding ketone. Source: NCERT

The second figure is the Friedel–Crafts acylation, the cleanest route to an aromatic ketone: benzene plus an acyl chloride, with anhydrous aluminium chloride as the catalyst, gives the aryl ketone directly. After this section, attempt the book’s worked Example 8.1 — it asks you to pick the reagent for each transformation, which is exactly the skill this table builds.

Nucleophilic Addition: The Reaction That Defines the Carbonyl Group

This is the idea the whole chapter turns on. Because the C=O is polar, the carbon is electrophilic, so nucleophiles add — and a whole list of reactions is the same mechanism with different nucleophiles.

Recap the mechanism from Fig. 8.2: perpendicular attack, sp² to sp³ rehybridisation, a tetrahedral alkoxide intermediate, then proton capture. Now the reactivity rule: aldehydes are more reactive than ketones for two reasons. Sterically, ketones have two groups blocking the approaching nucleophile. Electronically, two alkyl groups donate more electron density to the carbonyl carbon and lower its electrophilicity.

Resonance structures of benzaldehyde showing electron delocalisation that reduces the polarity of the carbonyl group
The carbon atom of the carbonyl group of benzaldehyde is less electrophilic than the one in propanal. Source: NCERT

The figure above explains a famous trap: resonance with the benzene ring reduces the carbonyl’s polarity, so benzaldehyde is less reactive than propanal toward nucleophiles — even though both are aldehydes.

Nucleophile Product Key point
HCN Cyanohydrin Base-catalysed; CN⁻ is the stronger nucleophile
NaHSO₃ Bisulphite addition product Equilibrium lies to the right for most aldehydes, left for most ketones — used to separate and purify aldehydes
Grignard reagent Alcohol Covered in the previous chapter
Alcohols Hemiacetal, then acetal Dry HCl catalyst
Diols Cyclic ketal e.g. ethylene glycol + ketone
Ammonia / H₂N–Z Imine, oxime, hydrazone, semicarbazone Book’s Table 8.2 lists all the derivatives
Acetal formation: dry hydrogen chloride protonates the carbonyl oxygen, increasing the carbon's electrophilicity so the alcohol can attack
Dry hydrogen chloride protonates the oxygen of the carbonyl compound and increases the electrophilicity of the carbonyl carbon. Source: NCERT

The acetal figure explains why dry HCl is needed: protonating the carbonyl oxygen pulls electron density away and makes the carbon more electrophilic, so the alcohol attack happens more readily. Remember the reverse too — acetals and ketals hydrolyse back to the carbonyl compound with aqueous mineral acid.

Reduction, Oxidation, Aldol and Cannizzaro Reactions

These reactions are how the chapter tells carbonyl compounds apart, and the oxidation tests here are the ones examiners reuse most.

Reduction. NaBH₄, LiAlH₄ or catalytic hydrogenation reduce aldehydes to primary alcohols and ketones to secondary alcohols. To remove the carbonyl completely, use the Clemmensen reduction (Zn–Hg with concentrated HCl) or the Wolff–Kishner reduction (hydrazine, then KOH in ethylene glycol) — both convert \( \textgreater\text{C=O} \) to \( \textgreater\text{CH}_2 \).

Oxidation. Aldehydes oxidise easily to carboxylic acids, even with mild agents: Tollens’ reagent gives a bright silver mirror, and Fehling’s reagent gives a red-brown Cu₂O precipitate. Aromatic aldehydes do not respond to Fehling’s test. Ketones need vigorous conditions, and their oxidation cleaves carbon–carbon bonds to give a mixture of smaller carboxylic acids.

Haloform reaction. Any aldehyde or ketone with a CH₃CO group — or a CH₃CH(OH) group that oxidises to one — gives a yellow precipitate with iodine and sodium hydroxide. This is the test for a methyl ketone.

Resonance-stabilised enolate anion showing why the alpha-hydrogens of carbonyl compounds are acidic
The acidity of α-hydrogen atoms of carbonyl compounds is due to the strong electron withdrawing effect of the carbonyl group and resonance stabilisation of the conjugate base. Source: NCERT

The figure above shows why α-hydrogens are acidic: the carbonyl withdraws electron density, and the conjugate base (the enolate) is stabilised by resonance. That acidity powers the next two reactions.

  • Aldol condensation: dilute alkali, needs at least one α-hydrogen, gives a β-hydroxy aldehyde or ketone (the aldol/ketol) that dehydrates to an α,β-unsaturated compound.
  • Cannizzaro reaction: concentrated alkali, requires no α-hydrogen; one molecule is oxidised to the acid salt and one is reduced to the alcohol (disproportionation).
Cross aldol condensation between two different aldehydes, each with alpha-hydrogens, giving a mixture of four products
Ketones can also be used as one component in the cross aldol reactions. Source: NCERT

The cross-aldol figure carries a warning: when two different aldehydes both have α-hydrogens, the mixture gives four products, because either molecule can act as the nucleophile or the electrophile.

Finally, aromatic aldehydes and ketones undergo electrophilic substitution on the ring, where the carbonyl group acts as a deactivating and meta-directing group.

Test Positive result What it tells you
Tollens’ (ammoniacal AgNO₃) Bright silver mirror Aldehyde present (ketones give nothing)
Fehling’s (CuSO₄ + Rochelle salt, alkaline) Red-brown Cu₂O precipitate Aliphatic aldehyde; aromatic aldehydes do not respond
2,4-DNP reagent Yellow, orange or red solid Aldehyde or ketone present
Iodoform (I₂ + NaOH) Yellow precipitate CH₃CO group (methyl ketone) or CH₃CH(OH) group
NaHCO₃ Brisk CO₂ effervescence Carboxylic acid (phenols do not react)

Carboxylic Acids: How They Are Prepared

Nearly every route to a carboxylic acid is either an oxidation or a hydrolysis. Once you see that, the list of methods shrinks to two ideas with several reagents.

Starting material Conditions Product / note
Primary alcohols, aldehydes KMnO₄ (neutral, acidic or alkaline); Jones reagent (CrO₃ + H₂SO₄) Carboxylic acid
Alkylbenzenes Vigorous oxidation (chromic acid or KMnO₄) Aromatic acid — the whole side chain becomes COOH
Nitriles, amides Hydrolysis with H⁺ or OH⁻ catalyst Nitrile → amide → acid (mild conditions stop at amide)
Grignard reagent CO₂ (dry ice), then acidify RMgX → RCOOH — adds one carbon
Acyl halides, anhydrides Water or aqueous base, then acidify Carboxylic acid
Esters Acidic hydrolysis (direct acid); basic hydrolysis then acidify Carboxylic acid
Vigorous oxidation of an alkylbenzene side chain to a benzoic acid, the whole side chain becoming a carboxyl group
Aromatic carboxylic acids can be prepared by vigorous oxidation of alkyl benzenes with chromic acid or acidic or alkaline potassium permanganate. Source: NCERT

Read one detail from the figure carefully: the entire side chain is oxidised to the carboxyl group, no matter how long it is — but tertiary side chains are not attacked. The nitrile and Grignard routes share a practical value: both convert an alkyl halide into an acid with one more carbon, ascending the series.

After this table, the book’s Example 8.5 is the right practice set.

Carboxylic Acids: Physical Properties and the Dimer

Physical properties follow from one idea — intermolecular forces — and the book compares carbonyl compounds with their neighbours to prove it. This ranking is the chapter’s own:

\( \text{n-butane} \lt \text{methoxyethane} \lt \text{propanal} \lt \text{acetone} \lt \text{propan-1-ol} \)

  • n-Butane boils lowest: only weak van der Waals forces.
  • Methoxyethane (an ether) is next — a small dipole, no hydrogen bonding.
  • Propanal and acetone sit above it because their dipole–dipole interactions are stronger than an ether’s.
  • Propan-1-ol boils highest because alcohol molecules associate through intermolecular hydrogen bonding.

So aldehydes and ketones boil higher than hydrocarbons and ethers of similar mass, but lower than alcohols of similar mass. The same logic explains solubility: the lower members (methanal, ethanal, propanone) are miscible with water because they hydrogen-bond with it, and solubility falls as the chain grows.

Two carboxylic acid molecules held together by two intermolecular hydrogen bonds in a cyclic dimer that survives in the vapour phase
In vapour state or in aprotic solvent, most carboxylic acids exist as dimers. Source: NCERT

Now the acid dimer, which explains why carboxylic acids boil higher than alcohols of comparable molecular mass: two acid molecules are held by two intermolecular hydrogen bonds in a cyclic dimer that survives even in the vapour phase and in aprotic solvents. Separating those molecules takes more energy, hence the higher boiling point.

The remaining facts follow: acids up to nine carbons are colourless liquids with unpleasant odours; higher ones are wax-like solids. Acids up to four carbons mix with water; solubility drops as the hydrocarbon chain grows, and benzoic acid is nearly insoluble in cold water. Acids stay soluble in less polar solvents like benzene, ether and chloroform.

Why Carboxylic Acids Are Acidic: pKa and Substituent Effects

This section answers the question the chapter keeps circling: why carboxylic acids are acidic, and why one acid is stronger than another. Start with the dissociation in water:

\[ \text{RCOOH} + \text{H}_2\text{O} \rightleftharpoons \text{H}_3\text{O}^+ + \text{RCOO}^- \]

The acid dissociation constant is \( K_a = \frac{[\text{H}_3\text{O}^+][\text{RCOO}^-]}{[\text{RCOOH}]} \), and \( pK_a = -\log K_a \). The smaller the pKa, the stronger the acid. The book’s reference values: trifluoroacetic acid 0.23, benzoic acid 4.19, acetic acid 4.76.

The core explanation — why acids beat phenols. The carboxylate conjugate base is stabilised by two equivalent resonance structures with the negative charge on the more electronegative oxygen. The phenoxide ion has more resonance structures, but they are non-equivalent and put the negative charge on less electronegative carbon atoms.

So carboxylate is more stabilised than phenoxide, and carboxylic acids are stronger acids than phenols and alcohols.

Electron withdrawing groups stabilising the carboxylate anion and strengthening the acid, while electron donating groups destabilise it
Effect of substituents on the acidity of carboxylic acids: electron withdrawing groups stabilise the carboxylate anion and strengthen the acid. Source: NCERT

The substituent figure shows the rule that orders every acidity question: electron withdrawing groups stabilise the conjugate base and raise acidity; electron donating groups destabilise it and lower acidity. The effect weakens with distance, so ClCH₂COOH is stronger than ClCH₂CH₂COOH. The book’s substituent order is Ph < I < Br < Cl < F < CN < NO₂ < CF₃.

Compress the full acid-strength order: CF₃COOH is the strongest, then acids carrying electron withdrawing groups, then formic acid, then benzoic acid, then acetic and higher alkyl acids. One twist worth remembering: direct phenyl or vinyl attachment raises acidity despite resonance donation, because the sp² carbon is more electronegative.

Reactions of Carboxylic Acids

Carboxylic acids react at three places — the O–H bond, the C–O bond, and the ring or α-carbon. Organising the list that way makes it manageable.

O–H bond cleavage: acids form salts with metals and alkalies, and — unlike phenols — they react with NaHCO₃ to evolve CO₂. That bicarbonate test is the standard way to detect a carboxyl group.

C–O bond reactions:

  • Anhydride formation on heating with H₂SO₄ or P₂O₅.
  • Esterification with alcohols in acid — a nucleophilic acyl substitution.
  • Acyl chloride formation with PCl₅, PCl₃ or SOCl₂. SOCl₂ is preferred because SO₂ and HCl are gases that escape, leaving a pure product.
  • Ammonia gives the ammonium salt, which on heating gives the amide.
Mechanism of esterification: protonation of the carbonyl oxygen, nucleophilic addition of the alcohol, proton transfer, loss of neutral water and deprotonation
Mechanism of esterification of carboxylic acids — a nucleophilic acyl substitution. Source: NCERT

Walk the esterification mechanism step by step from the figure: protonation of the carbonyl oxygen activates the carbonyl; the alcohol adds as a nucleophile; proton transfer in the tetrahedral intermediate converts –OH into –OH₂⁺, a better leaving group; neutral water is eliminated; the protonated ester finally loses a proton to give the ester.

Reduction: LiAlH₄ or diborane reduces acids to primary alcohols. NaBH₄ does not reduce the carboxyl group — a common trap.

Decarboxylation: heating the sodium salt with sodalime gives the hydrocarbon with one carbon fewer. Kolbe electrolysis of the aqueous salt gives a hydrocarbon with twice the carbons of the alkyl group.

α-Halogenation: Cl₂ or Br₂ with red phosphorus gives an α-halocarboxylic acid — the Hell–Volhard–Zelinsky reaction.

Electrophilic substitution on an aromatic carboxylic acid with the carboxyl group directing the incoming group to the meta position
Aromatic carboxylic acids undergo electrophilic substitution reactions in which the carboxyl group acts as a deactivating and meta-directing group. Source: NCERT

The ring-substitution figure ends the reactions: the carboxyl group is deactivating and meta-directing, and Friedel–Crafts reaction does not occur because the aluminium chloride catalyst binds to the carboxyl group.

Uses of Aldehydes, Ketones and Carboxylic Acids

This is a short, factual section — easy marks once the names are linked to their products. The pairings below are all from the book directly.

Compound Use
Methanal Formalin (40% solution) preserves biological specimens; makes bakelite and urea-formaldehyde glues
Ethanal Manufacture of acetic acid, ethyl acetate, vinyl acetate, polymers and drugs
Benzaldehyde Perfumery and dye industries
Acetone, ethyl methyl ketone Industrial solvents
Methanoic acid Rubber, textile, dyeing, leather and electroplating industries
Ethanoic acid Solvent and vinegar in the food industry
Hexanedioic acid Manufacture of nylon-6,6
Sodium benzoate Food preservative
Esters of benzoic acid Perfumery
Higher fatty acids Soaps and detergents

Common Mistakes Students Make in This Chapter

These are the traps the book itself flags through its summary, intext questions and final exercises. The wrong claim comes first in each row; the reasoning is NCERT’s.

Mistake Correct rule How to check your answer
“Benzaldehyde is more reactive than propanal toward nucleophiles.” Resonance with the ring reduces the carbonyl’s polarity, making benzaldehyde less electrophilic and less reactive. Ask where the carbonyl electrons can go — resonance lowers the positive character of the carbon.
“All aldehydes reduce Fehling’s solution.” Aromatic aldehydes do not respond to Fehling’s test. Tollens’ works for both aliphatic and aromatic aldehydes; Fehling’s only for aliphatic.
“Aldol condensation and Cannizzaro reaction need the same conditions.” Aldol uses dilute alkali and needs at least one α-hydrogen; Cannizzaro uses concentrated alkali and requires no α-hydrogen. Count the α-hydrogens on the carbonyl carbon’s neighbours first.
“NaBH₄ reduces carboxylic acids.” NaBH₄ does not reduce the carboxyl group. Use LiAlH₄ or diborane. NaBH₄ is the gentle reagent — it stops at alcohols only from aldehydes and ketones.
“Phenoxide has more resonance structures, so phenol should be the stronger acid.” More structures is not enough. The carboxylate ion’s two structures are equivalent, with charge on electronegative oxygen; phenoxide’s are non-equivalent, with charge on carbon. Compare where the negative charge actually sits, not how many arrows you can draw.
“Both NH₂ groups of semicarbazide react with the carbonyl.” Only the NH₂ attached to the C=O reacts (Exercise 8.18). The other NH₂ is part of the –NHCONH₂ unit and does not add.
“Number a ketone chain from either end; call every ring aldehyde benzaldehyde.” Number from the end nearer the carbonyl; a ring aldehyde gets the suffix carbaldehyde (benzaldehyde is accepted only for the unsubstituted parent). Write the structure and number it twice — the lower locant always wins.

Worked Example: Identifying a Carbonyl Compound Step by Step

Structure-determination problems combine the chapter’s tests in one question. Here is an original one with every step shown.

Problem.

An organic compound P has the molecular formula C₄H₈O.

It gives an orange-red precipitate with 2,4-DNP reagent and a yellow precipitate with iodine in sodium hydroxide, but it produces no silver mirror with Tollens’ reagent.

Vigorous oxidation of P gives ethanoic acid and propanoic acid.

Identify P and write the equations.

Step 1 — 2,4-DNP positive.

A 2,4-DNP derivative means P is an aldehyde or a ketone.

Step 2 — Tollens’ negative.

Ketones do not reduce Tollens’ reagent.

Since P gives no silver mirror, P is not an aldehyde — so P is a ketone.

Step 3 — iodoform positive.

The yellow precipitate proves a CH₃CO group, so P is a methyl ketone.

The only C₄H₈O methyl ketone is butan-2-one, CH₃COCH₂CH₃.

Step 4 — check with oxidation.

Vigorous oxidation of a ketone cleaves the carbon–carbon bonds beside the carbonyl:

\[ \text{CH}_3\text{COCH}_2\text{CH}_3 \xrightarrow[\text{heat}]{[\text{O}]} \text{CH}_3\text{COOH} + \text{CH}_3\text{CH}_2\text{COOH} \]

That gives ethanoic acid and propanoic acid — exactly what the problem states.

P is butan-2-one.

The iodoform equation:

\[ \text{CH}_3\text{COCH}_2\text{CH}_3 \xrightarrow{\text{I}_2/\text{NaOH}} \text{CHI}_3 \downarrow + \text{CH}_3\text{CH}_2\text{COONa} \]

Final answer: P is butan-2-one, CH₃COCH₂CH₃ — the yellow solid is iodoform (CHI₃) and the oxidation products confirm the structure.

One-line challenge. Which is stronger, 2-bromobutanoic acid or 3-bromobutanoic acid? The closer the electron-withdrawing bromine sits to the carboxyl group, the more it stabilises the conjugate base — so 2-bromobutanoic acid is the stronger acid.

How to Practise: Mapping the Chapter’s Exercises

The book closes the chapter with a large exercise set. Map each question to the skill it tests, and practise with intent instead of doing all twenty blindly.

Exercises Skill they test
8.1 Definitions of the ten terms — covered by the key-terms table on this page
8.2, 8.3, 8.4 IUPAC naming and drawing structures
8.5 Drawing derivatives of carbonyl compounds
8.6 Reactions of cyclohexanecarbaldehyde with Grignard, Tollens’, semicarbazide, ethanol in acid, and Zn–Hg/HCl
8.7 Deciding aldol vs Cannizzaro vs neither
8.8 Conversions starting from ethanal
8.9 Cross-aldol products from propanal and butanal
8.10, 8.11, 8.19 Structure determination from reactions — the method shown in the worked example on this page
8.12 Ordering reactivity towards HCN and ordering acid strength
8.13 Simple chemical tests to distinguish pairs of compounds
8.14 Syntheses starting from benzene
8.15 Two-step conversions
8.16 Describing named reactions: acetylation, Cannizzaro, cross aldol, decarboxylation
8.17 Completing syntheses from missing material, reagent or products
8.18 Reasoning explanations — including why only one NH₂ of semicarbazide reacts
8.20 Explaining why carboxylic acids are stronger acids than phenols

The intext questions embedded between the sections are quick self-checks — attempt each one as you finish the section it follows. Note that textbook contents and the examinable syllabus are not always identical — check the current official CBSE syllabus for what is examinable this session.

One-Screen Recap of the Whole Chapter

This table compresses each family into the three things you must be able to write in an exam answer: how it is made, what it does, and how to recognise it.

Family One-line preparation One-line key reaction One-line distinguishing test
Aldehydes Oxidation of primary alcohols (PCC), Rosenmund reduction, Stephen reaction Nucleophilic addition; easily oxidised to acids Tollens’ silver mirror (also positive for aromatic aldehydes); Fehling’s red-brown ppt (aliphatic only)
Ketones Oxidation of secondary alcohols, ozonolysis, alkyne hydration, Friedel–Crafts acylation Nucleophilic addition (slower than aldehydes); oxidation cleaves C–C bonds Iodoform test if it has a CH₃CO group; no Tollens’ mirror
Carboxylic acids Oxidation of alcohols/aldehydes/alkylbenzenes, nitrile hydrolysis, Grignard + CO₂ Esterification, acyl chloride formation, reduction to primary alcohols NaHCO₃ gives CO₂ effervescence — phenols do not

The named reactions are the chapter’s memory load. One table, all eleven:

Reaction Reagents What it makes Key condition
Rosenmund reduction H₂ / Pd-BaSO₄ Aldehyde from acyl chloride Poisoned catalyst stops at aldehyde
Stephen reaction SnCl₂ + HCl, then hydrolysis Aldehyde from nitrile Goes through the imine
Etard reaction CrO₂Cl₂, then hydrolysis Benzaldehyde from toluene Stops oxidation at aldehyde stage
Gatterman–Koch CO + HCl, AlCl₃ or CuCl Benzaldehyde from benzene Formylation of the ring
Friedel–Crafts acylation Acyl chloride + anhydrous AlCl₃ Aryl ketone from benzene Anhydrous conditions
Clemmensen reduction Zn–Hg + conc. HCl \( \textgreater\text{CH}_2 \) from \( \textgreater\text{C=O} \) Acidic conditions
Wolff–Kishner reduction NH₂NH₂, then KOH / ethylene glycol \( \textgreater\text{CH}_2 \) from \( \textgreater\text{C=O} \) Basic conditions, heat
Aldol condensation Dilute alkali β-Hydroxy carbonyl, then α,β-unsaturated compound At least one α-hydrogen
Cannizzaro reaction Concentrated alkali Alcohol + acid salt No α-hydrogen
Hell–Volhard–Zelinsky Cl₂ or Br₂ + red phosphorus α-Halocarboxylic acid α-Position halogenation
Kolbe electrolysis Electrolysis of aqueous sodium salt Hydrocarbon with twice the carbons Decarboxylative coupling

The big ideas in one breath: the polar carbonyl drives nucleophilic addition; aldehydes are more reactive than ketones; the presence of an α-hydrogen decides between aldol and Cannizzaro; carboxylate resonance decides acidity; and Tollens’ and Fehling’s tests separate aldehydes from ketones.

Physically, carbonyl compounds are polar, the small ones hydrogen-bond with water, and carboxylic acids associate into hydrogen-bonded dimers — which is why they boil highest of the three families.

This chapter builds directly on alcohol oxidation and Grignard chemistry from the previous chapter, and its acid derivatives lead into the amines chapter. The notes below cover both directions and the surrounding course.

Sources and Data Verification

This page describes the NCERT Class 12 Chemistry Part II textbook, Chapter 3, “Aldehydes, Ketones and Carboxylic Acids”, from the current NCERT reprint as published on ncert.nic.in.

  • What the page covers: the chapter’s contents and study guidance — not the CBSE syllabus, which is set separately by CBSE.
  • Which books: the NCERT Class 12 Chemistry Part II textbook, Chapter 3 only; it does not cover other chapters or books.
  • Academic session: the page is maintained for the current session using the NCERT information available to us.
  • Who settles what: NCERT settles textbook editions and PDFs; CBSE settles the curriculum, syllabus and examinations.
  • Figures and counts shown here come from the textbook itself. No external expert review is claimed.

Reference: NCERT Class 12 Chemistry Part II textbook, chapter 3, official edition on ncert.nic.in.

Quick Answers to Common Questions

Why are aldehydes more reactive than ketones in nucleophilic addition reactions?

Two reasons. Sterically, a ketone has two relatively large substituents blocking the approach of the nucleophile, while an aldehyde has only one. Electronically, two alkyl groups donate more electron density to the carbonyl carbon and lower its electrophilicity more effectively than one does. Both effects make the aldehyde’s carbonyl carbon a better target for attack.

Why does benzaldehyde not respond to Fehling’s test even though it is an aldehyde?

Fehling’s test works only for aliphatic aldehydes — the book states plainly that aromatic aldehydes do not respond to this test. If you need to test an aromatic aldehyde, use Tollens’ reagent, which does give a silver mirror for benzaldehyde.

What is the difference between aldol condensation and Cannizzaro reaction?

The deciding factor is the α-hydrogen. Aldol condensation needs at least one α-hydrogen and uses dilute alkali, building a β-hydroxy carbonyl compound. Cannizzaro reaction happens with aldehydes that have no α-hydrogen, uses concentrated alkali, and is a disproportionation — one molecule is oxidised to the acid salt while another is reduced to the alcohol.

Why is formic acid a stronger acid than acetic acid?

Acetic acid carries a methyl group, and alkyl groups donate electron density. That donation destabilises the acetate conjugate base, so acetic acid is weaker. Formic acid has only a hydrogen attached, so its conjugate base is more stable — hence formic acid is the stronger acid (the book’s acidity order shows HCOOH above CH₃COOH).

Which reagents reduce a carboxylic acid to a primary alcohol?

Lithium aluminium hydride (LiAlH₄) or diborane. Sodium borohydride, NaBH₄, does not reduce the carboxyl group — that is a common trap. NaBH₄ is fine for reducing aldehydes and ketones to alcohols, but a carboxylic acid needs the stronger reagent.

How can propanal and propanone be distinguished in the laboratory?

Use Tollens’ or Fehling’s test: propanal (an aldehyde) gives a silver mirror with Tollens’ reagent and a red-brown precipitate with Fehling’s solution, while propanone gives nothing in either. Alternatively, use the iodoform test — propanone has a CH₃CO group and gives a yellow precipitate with iodine and sodium hydroxide, which propanal does not.


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